If P(θ) is a point on the unit circle, then the coordinates of P (5/6π) are:
a)√3/2, 1/2
b) -√3/2, 1/2
c) √3/2, -1/2
d) -√3/2, -1/2
It is just a matter of finding where on the Unit Circle is 5/6π and using the corresponding triangle to determine the coordinates.
If you are unfamiliar with the Unit Circle and degrees is more your style than you can convert radians to degrees. (5/6π) (180)= 150 degrees
So now we know where our triangle is on the Unit Circle:
Since we are at 150 degrees, a 30-60-90 triangle is generated. Now you just plug in your sides of the triangle by setting your hypotenuse at 1. Now you know the coordinates are:
x=-√3/2 y=1/2 or -√3/2, 1/2
The answer than is b)
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